Q^2+12Q-133=0

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Solution for Q^2+12Q-133=0 equation:


Simplifying
Q2 + 12Q + -133 = 0

Reorder the terms:
-133 + 12Q + Q2 = 0

Solving
-133 + 12Q + Q2 = 0

Solving for variable 'Q'.

Factor a trinomial.
(-19 + -1Q)(7 + -1Q) = 0

Subproblem 1

Set the factor '(-19 + -1Q)' equal to zero and attempt to solve: Simplifying -19 + -1Q = 0 Solving -19 + -1Q = 0 Move all terms containing Q to the left, all other terms to the right. Add '19' to each side of the equation. -19 + 19 + -1Q = 0 + 19 Combine like terms: -19 + 19 = 0 0 + -1Q = 0 + 19 -1Q = 0 + 19 Combine like terms: 0 + 19 = 19 -1Q = 19 Divide each side by '-1'. Q = -19 Simplifying Q = -19

Subproblem 2

Set the factor '(7 + -1Q)' equal to zero and attempt to solve: Simplifying 7 + -1Q = 0 Solving 7 + -1Q = 0 Move all terms containing Q to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1Q = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1Q = 0 + -7 -1Q = 0 + -7 Combine like terms: 0 + -7 = -7 -1Q = -7 Divide each side by '-1'. Q = 7 Simplifying Q = 7

Solution

Q = {-19, 7}

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